/* An interview question to find even or odd. */
#include<stdio.h>
#include<conio.h>
void main()
{
int n;
printf("Enter the number: ");
scanf("%d",&n);
if(n & 1)
printf("Odd");
else
printf("Even");
getch();
}
Method 2:
#include<stdio.h>
#include<conio.h>
void main()
{
int n;
float b,c;
clrscr();
printf("Enter the number: ");
scanf("%d",&n);
b=n/2.0;
c=b-(int)b;
if(c==0)
printf("\nEven");
else
printf("\nOdd");
getch();
}
Method 3:
#include<stdio.h>
#include<conio.h>
void main()
{
int n;
clrscr();
printf("Enter the number: ");
scanf("%d",&n);
if((n/2)*2==n)
printf("Even");
else
printf("Odd");
getch();
}
If you want explanation then do comment....
#include<stdio.h>
#include<conio.h>
void main()
{
int n;
printf("Enter the number: ");
scanf("%d",&n);
if(n & 1)
printf("Odd");
else
printf("Even");
getch();
}
Method 2:
#include<stdio.h>
#include<conio.h>
void main()
{
int n;
float b,c;
clrscr();
printf("Enter the number: ");
scanf("%d",&n);
b=n/2.0;
c=b-(int)b;
if(c==0)
printf("\nEven");
else
printf("\nOdd");
getch();
}
Method 3:
#include<stdio.h>
#include<conio.h>
void main()
{
int n;
clrscr();
printf("Enter the number: ");
scanf("%d",&n);
if((n/2)*2==n)
printf("Even");
else
printf("Odd");
getch();
}
If you want explanation then do comment....
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