/* Armstrong number Eg if abc is a number then if (a^3+b^3+c^3=abc) then number is armstrong now
Let number is abcd the if (a^4+b^4+c^4+d^4=abcd) then number is armstron.
Note: Power to each digit must be equal to number of digits of the given number */
#include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{
int n,i=0,s=0,t=0,r=0,k=1;
clrscr();
printf("Enter the number : ");
scanf("%d",&n);
for(k=1;k<n;k++)
{
i=k;
while(i>0)
{
i=i/10;
t++;
}
for(i=k;i>0;i=i/10)
{
r=i%10;
s= s+pow(r,t);
}
if(s==k)
printf(" %d ",k);
}
getch();
}
/*for example enter n=10000//
output will be 1 2 3 4 5 6 7 8 9 153 370 371 407 1634 8208 9474
these are Armstrong number between 1 to 10000
verification 1^1=1 similarly for 153; 1^3+5^3+3^3=1+125+27=153
and for 1634; 1^4+6^4+3^4+4^4=1+1296+81+256=1634*/
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